Integrand size = 29, antiderivative size = 25 \[ \int (a+i a \tan (e+f x)) (c-i c \tan (e+f x))^3 \, dx=\frac {i a (c-i c \tan (e+f x))^3}{3 f} \]
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Time = 0.08 (sec) , antiderivative size = 25, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.103, Rules used = {3603, 3568, 32} \[ \int (a+i a \tan (e+f x)) (c-i c \tan (e+f x))^3 \, dx=\frac {i a (c-i c \tan (e+f x))^3}{3 f} \]
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Rule 32
Rule 3568
Rule 3603
Rubi steps \begin{align*} \text {integral}& = (a c) \int \sec ^2(e+f x) (c-i c \tan (e+f x))^2 \, dx \\ & = \frac {(i a) \text {Subst}\left (\int (c+x)^2 \, dx,x,-i c \tan (e+f x)\right )}{f} \\ & = \frac {i a (c-i c \tan (e+f x))^3}{3 f} \\ \end{align*}
Both result and optimal contain complex but leaf count is larger than twice the leaf count of optimal. \(55\) vs. \(2(25)=50\).
Time = 0.22 (sec) , antiderivative size = 55, normalized size of antiderivative = 2.20 \[ \int (a+i a \tan (e+f x)) (c-i c \tan (e+f x))^3 \, dx=\frac {a c^3 \left (3 f x-3 \arctan (\tan (e+f x))+3 \tan (e+f x)-3 i \tan ^2(e+f x)-\tan ^3(e+f x)\right )}{3 f} \]
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Time = 0.17 (sec) , antiderivative size = 21, normalized size of antiderivative = 0.84
method | result | size |
derivativedivides | \(-\frac {a \,c^{3} \left (\tan \left (f x +e \right )+i\right )^{3}}{3 f}\) | \(21\) |
default | \(-\frac {a \,c^{3} \left (\tan \left (f x +e \right )+i\right )^{3}}{3 f}\) | \(21\) |
risch | \(\frac {8 i a \,c^{3}}{3 f \left ({\mathrm e}^{2 i \left (f x +e \right )}+1\right )^{3}}\) | \(24\) |
parallelrisch | \(-\frac {3 i a \,c^{3} \left (\tan ^{2}\left (f x +e \right )\right )+\left (\tan ^{3}\left (f x +e \right )\right ) a \,c^{3}-3 \tan \left (f x +e \right ) a \,c^{3}}{3 f}\) | \(47\) |
norman | \(\frac {a \,c^{3} \tan \left (f x +e \right )}{f}-\frac {a \,c^{3} \left (\tan ^{3}\left (f x +e \right )\right )}{3 f}-\frac {i a \,c^{3} \left (\tan ^{2}\left (f x +e \right )\right )}{f}\) | \(51\) |
parts | \(a \,c^{3} x -\frac {i a \,c^{3} \ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{f}-\frac {2 i a \,c^{3} \left (\frac {\left (\tan ^{2}\left (f x +e \right )\right )}{2}-\frac {\ln \left (1+\tan ^{2}\left (f x +e \right )\right )}{2}\right )}{f}-\frac {a \,c^{3} \left (\frac {\left (\tan ^{3}\left (f x +e \right )\right )}{3}-\tan \left (f x +e \right )+\arctan \left (\tan \left (f x +e \right )\right )\right )}{f}\) | \(98\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 45 vs. \(2 (19) = 38\).
Time = 0.23 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.80 \[ \int (a+i a \tan (e+f x)) (c-i c \tan (e+f x))^3 \, dx=\frac {8 i \, a c^{3}}{3 \, {\left (f e^{\left (6 i \, f x + 6 i \, e\right )} + 3 \, f e^{\left (4 i \, f x + 4 i \, e\right )} + 3 \, f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 66 vs. \(2 (19) = 38\).
Time = 0.15 (sec) , antiderivative size = 66, normalized size of antiderivative = 2.64 \[ \int (a+i a \tan (e+f x)) (c-i c \tan (e+f x))^3 \, dx=\frac {8 i a c^{3}}{3 f e^{6 i e} e^{6 i f x} + 9 f e^{4 i e} e^{4 i f x} + 9 f e^{2 i e} e^{2 i f x} + 3 f} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 45 vs. \(2 (19) = 38\).
Time = 0.29 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.80 \[ \int (a+i a \tan (e+f x)) (c-i c \tan (e+f x))^3 \, dx=-\frac {a c^{3} \tan \left (f x + e\right )^{3} + 3 i \, a c^{3} \tan \left (f x + e\right )^{2} - 3 \, a c^{3} \tan \left (f x + e\right )}{3 \, f} \]
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 45 vs. \(2 (19) = 38\).
Time = 0.42 (sec) , antiderivative size = 45, normalized size of antiderivative = 1.80 \[ \int (a+i a \tan (e+f x)) (c-i c \tan (e+f x))^3 \, dx=\frac {8 i \, a c^{3}}{3 \, {\left (f e^{\left (6 i \, f x + 6 i \, e\right )} + 3 \, f e^{\left (4 i \, f x + 4 i \, e\right )} + 3 \, f e^{\left (2 i \, f x + 2 i \, e\right )} + f\right )}} \]
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Time = 5.61 (sec) , antiderivative size = 34, normalized size of antiderivative = 1.36 \[ \int (a+i a \tan (e+f x)) (c-i c \tan (e+f x))^3 \, dx=-\frac {a\,c^3\,\mathrm {tan}\left (e+f\,x\right )\,\left ({\mathrm {tan}\left (e+f\,x\right )}^2+\mathrm {tan}\left (e+f\,x\right )\,3{}\mathrm {i}-3\right )}{3\,f} \]
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